(高一数学)设函数f(x)=ax+bx+1(a,b是实数)满足:
设函数f(x)=ax+bx+1(a,b是实数)满足:f(-1)=0,且对任意实数x均有f(x)≥0成立.(1)求实数a,b的值(2)当x属于[-2,2]时,求函数g(x)=ax+btx+1的最大值h(t)