xyz=1对x求导得yz+x(dy/dx)z+xy(dz/dx)=0(1)z=x²+y²对x求导得dz/dx=2x+2y(dy/dx)(2)(2)代入(1)得yz+xz(dy/dx)+xy[2x+2y(dy/dx)]=0解得dy/dx=-[yz+2x²y]/[xz+2xy²]dz/dx=2x+2y(dy/d...
xyz=1对x求导得yz+x(dy/dx)z+xy(dz/dx)请问这个是怎么弄的啊?
利用的乘法的导数公式(uv)'=u'v+uv'(xyz)'=x'yz+x(yz)'=x'yz+x(y'z+yz')