(2012•厦门)已知平行四边形ABCD,对角线AC和BD相交于点O,点P在边AD上,过点P作PE⊥AC,PF⊥BD,垂足分别为E、F,PE=PF.
(1)如图,若PE=
3
(2)若点P是AD的中点,点F是DO的中点,BF=BC+3
2