医学统计学中G=log-1[1/52×(3log40+22log80+…+log1280)]=129.3是怎么算的,log-1...
log^-1(A)=log(A)^-1?,还是log^-1(A)=log(A^-1)?,真心弄不懂
已经明白了,log^-1(A)=10^A