（xy-1）²+（x+y-2）（x+y-2xy）因式分解
更新时间： 2025-08-18 00:58:28
1人问答
问题描述：
（xy-1）²+（x+y-2）（x+y-2xy）因式分解
楼俊君回答：
x+y-2xy)(x+y-2)+(xy-1)2
=(x+y)2-2xy(x+y)-2(x+y)+4xy+(xy)2-2xy+1
=[(x+y)2-2xy(x+y)+(xy)2]-2(x+y-xy)+1
=(x+y-xy)2-2(x+y-xy)+1
=[(x+y-xy)-1]2
=(-xy+x+y-1)2
=[-x(y-1)+(y-1)]2
=[(y-1)(1-x)]2
=(x-1)2*(y-1)2
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